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The straight line through two points will have an equation in the form \(y = mx + c\). Then, we can find the value of \(c\), the \(y\)-intercept, by substituting the coordinates of one point into the ...

If a quadratic equation can be factorised, the factors can be used to find the roots of the equation. The equation factorises to give \((x + 3) (x - 2) = 0 \) so the solutions to the equation \(x^2 + ...